16.1t^2-45.9t-14=0

Solution for 16.1t^2-45.9t-14=0 equation:

16.1t^2-45.9t-14=0

a = 16.1; b = -45.9; c = -14;
Δ = b2-4ac
Δ = -45.92-4·16.1·(-14)
Δ = 3008.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45.9)-\sqrt{3008.41}}{2*16.1}=\frac{45.9-\sqrt{3008.41}}{32.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45.9)+\sqrt{3008.41}}{2*16.1}=\frac{45.9+\sqrt{3008.41}}{32.2}
$